Integral sin² 2x dx

Karena:
2sin²a = 1 - cos(2a)
sin²a = 1/2 (1 - cos(2a))
Maka:
sin²(2x) = 1/2 (1 - cos(4x))
Sehingga:

integral sin^2 2x dx
=integral 1/2(1-cos4x)dx
=integral 1/2-1/2 cos 4x dx
=1/2x-1/2.1/4 sin 4x
=1/2x-1/8 sin4x +c