jika diketahui f¹(x)=3(x²-3) dan f(1)=12 tentukan fungsi f(x)

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f ' (x) = 3(x² -3) = 3x² - 9
f(x)= ∫ f'(x) dx = ∫(3x² -9) dx
f(x)= x³ - 9x + c
f(1) = 12
1³ -9(1) +c= 12
1 - 9 + c = 12
-8 + c = 12
c = 12 + 8
c = 20
f(x) = x³ - 9x + 20