3 tan 5x+√3 =0,° ≤×≤ 360° tentykan hpbdari persamaan trigonometri tsb

3 tan 5x + √3 = 0
3 tan 5x = -√3
tan 5x = -√3/3
tan 5x = tan 60
5x = 60
x = 60/5 = 12
tan 5x = tan (180+60)
5x = 240
x = 240/5 = 48
tan 5x = tan (360+60)
5x = 420
x = 84
tan 5x = tan (360+240)
5x = 600
x = 120
tan 5x = tan (2.360+60)
5x = 780
x = 156
tan 5x = tan (2.360+240)
5x = 960
x = 192
tan 5x = tan (3.360+60)
5x = 1140
x = 228
tan 5x = tan (3.360+240)
5x = 1320
x = 264
tan 5x = tan (4.360+60)
5x = 1500
x = 300
tan 5x = tan (4.360+240)
5x = 1680
x = 336
hp {12, 48, 84, 120, 156, 192, 228, 264, 300, 336}