No 1. F(x)=5 F'(-2)=-7 F(2)=4 2. F(x) =10x pangkat 4, F' (-1) =-5 F(0) = 8 Tolong d jawab punya adek, besok d kumpul!!!!! Makasih sebelumnya

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f' (x) = ∫ f'(x) dx = ∫ 5 dx
f '(x)= 5x+ c
f '(-2) = -7
5(-2) + c = - 7
-10 + c =- 7c = 3
f'(x) = 5x  + 3
f(x)= ∫ f'(x)= ∫ (5x + 3) dx
f (x) = 5/2 x² + 3x + c
f(2)= 4
5/2 (2)² + 3(2)+ c = 4
10 + 6 + c = 4
16 + c = 4
c = -12
f(x)= 5/2 x² +3x - 12

f'(x)= ∫ f " (x) dx = ∫ (10x⁴) dx
f  '(x)= 2x⁵ + c
f'(-1) = - 5
-5 = 2(-1)⁵ + c
-5 = -2 + c
c = -3
f '(x)= 2x⁵- 3
f (x) = ∫ f '(x) dx = ∫ (2x⁵ -3) dx
f (x) = 1/3 x⁶ - 3x + c
f(0) = 8
8 = 1/3 (0) - 3(0) + c
c = 8
f(x)= 1/3 x⁶ - 3x + 8