Klw cara jalan soal ini gmn, please

Penyelesaian:

Ingat: a^m . a^n = a^m+n
a^m / a^n = a^m-n
(a^m)^n = a^mn

4. a. 216^2/3 
= (6^3)^2/3
= 6^2 = 36

b. 81^3/4 
= (3^4)^3/4
= 3^3 = 27

5. [tex] \frac{2^4 . 9^-2 . 5^-3}{8 . 3^-5 . 125^-1} [/tex]
= [tex] \frac{2^4 . (3^2)^-2 . 5^-3}{2^3 . 3^-5 . (5^3)^-1} [/tex]
= 2 . 9 . 5^0
= 18