.......°C=.......°R=122°F=.......°K
Matematika
FebriYnt
Pertanyaan
.......°C=.......°R=122°F=.......°K
1 Jawaban
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1. Jawaban Kalpataru
F = 122°
C = 5/9 × (122 - 32) = 50°
R = 4/9 × (122 - 32) = 40°
K = C + 273° = 50° + 273° = 323°