f'(x) = 6x^2 - 2x + 7 dan f(2) = 12 tentukan rumus fungsi

F(x) = ∫ 6x² - 2x + 7
        = 6/3 . x²⁺¹ - 2/2 . x¹⁺¹ + 7/1 . x⁰⁺¹
        =  2x³ - x² + 7x
F(2) = 2(2)³ - (2)² + 7(2) + c = 12
        = 16 - 4 + 14 + c = 12
            26 + c = 12
                     c = -13
maka rumus fungsi :
f(x) = 2x³ - x² + 7x - 13

f'(x) = 6x² - 2x + 7

u/ f(2) = 12
f(2) = 6x² - 2x + 7 = 12
f(2) = 6(2)² - 2(2) + 7 = 12
f(2) = 6(4) - 4 + 7 = 12
f(2) = 24 - 4 + 7 = 12
f(2) = 24 + 3 = 12
f(2) = 27 = 12
f(2) = 12 - 27
f(2) = -15

smoga brmanfaat.