himpunan penyelesaian persamaan 2|2×+1|=4

Matematika Wajib
Persamaan Mutlak X SMA

Pembahasan :
Jika 2 itu bukan nomor ↓
2|x + 1| = 4
|x + 1| = 2
(x + 1)² = 2²
(x + 1)² - 2² = 0
(x + 1 + 2)(x + 1 - 2) = 0
(x + 3)(x - 1) = 0
x = -3
x = 1

Hp : {-3 , 1}

Atau Pakai Cara lain :

2|x + 1| = 4
|x + 1| = 2

x + 1 = 2
x = 2 - 1
x = 1

x + 1 = -2
x = -2 - 1
x = -3

Hp : {-3 , 1}

————————————————
Jika 2 itu nomor ↓
|x + 1| = 4
(x + 1)² = 4²
(x + 1)² - 4² = 0
(x + 1 + 4)(x + 1 - 4) = 0
(x + 5)(x - 3) = 0
x = -5
x = 3

Hp : {-5 , 3}

Atau Pakai Cara lain :

|x + 1| = 4

x + 1 = 4
x = 4 - 1
x = 3

x + 1 = -4
x = -4 - 1
x = -5

Hp : {-5 , 3}