cos = -1/2akar 3,0°< x < 360°
Matematika
NuriHidayatiFitri
Pertanyaan
cos = -1/2akar 3,0°< x < 360°
1 Jawaban
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1. Jawaban BSunShine
Bab : Persamaan Trigonometri
Kelas : XI SMA
cos x = -1/2 V3
cos x = cos 150°
x = 150°
Rumus cos :
=> x = cos x + k . 360
=> x = - cos x + k . 360
Step I :
x = cos x + k. 360°
x = 150° + k . 360°
----------------------------
k = 0
=> 150° + 0.360° = 150° ( M )
k = 1
=> 150° + 1.360° = 510° ( TM )
Step II :
x = -cos x + k. 360°
x = -150° + k . 360°
----------------------------
k = 0
=> -150° + 0. 360° = -150° ( TM )
k = 1
=> -150° + 1. 360° = 210° ( M )
k = 2
=> -150° + 2 . 360° = 570° ( TM )
Jadi , Hp = { 150° , 210° }