Matematika

Pertanyaan

cos = -1/2akar 3,0°< x < 360°
cos = -1/2akar 3,0°< x < 360°

1 Jawaban

  • Bab : Persamaan Trigonometri
    Kelas : XI SMA

    cos x = -1/2 V3
    cos x = cos 150°
    x = 150°

    Rumus cos :
    => x = cos x + k . 360
    => x = - cos x + k . 360


    Step I :

    x = cos x + k. 360°
    x = 150° + k . 360°
    ----------------------------
    k = 0
    => 150° + 0.360° = 150° ( M )
    k = 1
    => 150° + 1.360° = 510° ( TM )

    Step II :

    x = -cos x + k. 360°
    x = -150° + k . 360°
    ----------------------------
    k = 0
    => -150° + 0. 360° = -150° ( TM )
    k = 1
    => -150° + 1. 360° = 210° ( M )
    k = 2
    => -150° + 2 . 360° = 570° ( TM )

    Jadi , Hp = { 150° , 210° }