[tex]( \sqrt{28} - \sqrt{12})( 2\sqrt{7} +2 \sqrt{3}) [/tex] Minta tolong beserta caranya

Penyelesaian:

[tex]( \sqrt{28} - \sqrt{12})( 2\sqrt{7} + 2\sqrt{3}) [/tex]
= [tex]( \sqrt{4.7} - \sqrt{4.3})( 2\sqrt{7} + 2\sqrt{3})[/tex]
= [tex] (2\sqrt{7} - 2\sqrt{3})( 2\sqrt{7} + 2\sqrt{3}) [/tex]
= 4(7) - 4(3)
= 28 - 12 = 16

(√28 - √12) (2√7 + 2√3)
= (√4×7 - √4×3) (2√7 + 2√3)
= (2√7 - 2√3) (2√7 + 2√3)

ingat, (a+b)(a-b) = a² - b²

(2√7)² - (2√3)²
= (4 × 7) - (4 × 3)
= 28 - 12
= 16