hitung titik didih dan titik beku larutan glikol 20% massa ! ( Mr=62,Kb=0,52,Kf=1,86 )

dik
mr= 62
kb=0,52
kf=1,86
misalkan 100 gram larutan 20%, maka terdapat 20 gram glikol dan 80 gram air

∆T= [ 20/60 ] × [ 1000/80] × 0,52 = 2,1°C

titik didih larutan glikol = 100 + 2,1 = 102,1°C

penurunan titik beku =[ massa/Mr] ×[1000/massa air] ×kf
kf= 1,86

∆T= [20/62] ×[1000/80]× 1,86 = 7,5°C

titik beku larutan glikol = 0- 7,5°C= -7,5°C