tolong si 2 soal itu lagi butuh bgt tolongg, jawabannya yg jelas dan benar makasih

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₁∫ᵃ (4x -3) dx = 10
|2x² - 3x|ᵃ₁ = 10
2a² - 3a - (2-3) = 10
2a² -3a + 1 -10 = 0
2a² -3a - 9 = 0
(2a + 3)(a -3) = 0
2a + 3 = 0
a = - 3/2
a - 3 = 0
a = 3
a > 1
a = 3

₋₁∫ᵃ (3x² -2)dx = 3
=|x³ - 2x|ᵃ₋₁ = 3
a³ - 2a - (-1 +2) = 3
a³ - 2a - 1 - 3 = 0
a³ - 2a - 4 = 0
(a-2)(a²+2a+2) =0
a-2 = 0
a = 2