tentukan jenis stasioner dari fungsi f(x) = 2x(3)-9x(2)+12

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f(x) = 2x³ - 9x² + 12
f'(x) = 0
6x² -18x =0
6x(x - 3) = 0
x= 0,
y = 2(0)³ - 9(0)² +12
y = 12
(x,y) = (0,12)
x = 3
y = 2(3)³ -9(3)² + 12
y = 54 - 81 + 12
y = -15
(x,y)=(3, -15)

f "(x) = 12x - 18
f"(0) = 12(0) - 18 = -18
f " (0) < 0
titik (0,12) titik maksimum

f"(x) = 12x - 18
f"(3) = 12(3) - 18 = 18
f"(3)> 0
titik (3, -15) titik minimum