1 per x²y × 2x per 3y² × 5 per 3x × (4y)²
Matematika
Deviptrmhrn
Pertanyaan
1 per x²y × 2x per 3y² × 5 per 3x × (4y)²
1 Jawaban
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1. Jawaban SadonoSukirno
1/x²y × 2x/3y² × 5/3x × (4y)²
= 1/x²y × 2x/3y² × 5/3x × 16y²
= (1×(2/3)×(5/3)×16) . x^(-2+1-1) . y^(1-2+2)
= 160/9 . x^-2 . y^1
= 160y/9x²
^ tanda pangkat