2per3+2satuper2+3satuper4

2/3+3/2+13/4=2/3+3/2+13/4=8+9+39/12=56/12=4duapertiga

[tex] \frac{2}{3} + 2\frac{1}{2} + 3\frac{1}{4} = \frac{8}{12} +2 \frac{6}{12} +3 \frac{3}{12} = 5 \frac{17}{12} = 6 \frac{5}{12} [/tex]