1. tentukan nilai dari ^2 log 48 - ^2 log 36 + ^2 log 12 2. Diket ^2 log 3 = a, ^2 log 5 = b. Tentukan nilai ^6 log 45 3. Tentukan nilai dari ^2 log 9 x ^3 log

1. ²log 48 - ²log 36 + ²log 12
   = ²log (48 : 36 x 12)
   = ²log 16
   = ²log 2⁴
   = 4

2. ²log 3 = a  dan ²log 5 = b
   6 log 45
  = [tex] \frac{ ^{2} log 45}{ ^{2} log 6} [/tex]
  = [tex] \frac{ ^{2} log 3^2 . 5}{ ^{2} log 2.3} [/tex]
  = [tex] \frac{2a+b}{1+a} [/tex]

3. ²log 9 x ³log 16 x ⁴log 32
   = ²log 3² x ³log 4² x ⁴log 2⁵
   = ²log 3 x ³log 4 x ⁴log 2 x 2 x 2 x 5
   = ²log 2 x 20
   = 1 x 20
   = 20

4. [tex] \frac{3}{ \sqrt{5} + \sqrt{2} } [/tex]
   = [tex] \frac{3}{ \sqrt{5} + \sqrt{2} } [/tex] x [tex] \frac{ \sqrt{5} - \sqrt{2} }{ \sqrt{5} - \sqrt{2} } [/tex]
   = [tex] \frac{3( \sqrt{5} - \sqrt{2}) }{5 - 2} [/tex]
   = [tex] \frac{3( \sqrt{5} - \sqrt{2} )}{3} [/tex]
   = [tex] \sqrt{5} - \sqrt{2} [/tex]

5. f(x) = ax + b
     8 = a + b --> a = 8-b
     1 = 2a + b
     1 = 2 (8-b) + b
     1 = 16 - 2b + b
      b = 15
       a = 8-15
       a = -7
  f (x) = -7x + 15

1.²log(48 : 36 x 12)=²log16=4
2.∧6log45=²log45/²log6=b+2a/1+a
3.²log3²x³log4²x[tex] ^{4}log2 ^{5} [/tex]=5
4.3 per √5+√2=3√5-3√2 per 5-2=√5-√2
5.a+b=8
   2a+b=1
   a=-7
   b=15